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For the hypothetic reaction, the equilib...

For the hypothetic reaction, the equilibrium constant (K) values are given
`A hArr B,K_(1)=2.0 `
`B hArr C, K_(2)=4.0`
`ChArr D, K_(3) =3.0`
The equilibrium constant for the reaction
`A hArr D` is

A

48

B

6

C

`2.7`

D

12

Text Solution

Verified by Experts

`K_(1)=([B])/([A])=2.00,K_(2)=([C])/([B])=4.00 K_(3)=([D])/([C])=3.00`
For the reaction `A hArrD`
`K=([D])/([A])=([D])/([C])xx([C])/([B])xx([B])/([A])=K_(1)xxK_(2)xxK_(3)=3xx4xx2=24`
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