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The correct relation between hydrolysis ...

The correct relation between hydrolysis constant `(K_(b))` and degree of hydrolysis `(alpha)` for the following equilibrium is

A

`alpha = sqrt((K_(w).C)/(K_(a)))`

B

`alpha = sqrt((K_(w))/(K_(a).C))`

C

`alpha = sqrt((K_(a).C)/(K_(w))`

D

`alpha = sqrt((K_(a))/(K_(w).C))`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the correct relationship between the hydrolysis constant \( K_b \) and the degree of hydrolysis \( \alpha \), we can follow these steps: ### Step 1: Understand Hydrolysis Hydrolysis is a reaction involving the reaction of a salt with water, resulting in the formation of an acid and a base. For example, when ammonium chloride (\( NH_4Cl \)) is dissolved in water, it undergoes hydrolysis to produce ammonium ions (\( NH_4^+ \)) and chloride ions (\( Cl^- \)). The chloride ion does not undergo hydrolysis because it comes from a strong acid (HCl). ### Step 2: Write the Hydrolysis Reaction For the hydrolysis of \( NH_4Cl \): \[ NH_4^+ + H_2O \rightleftharpoons NH_3 + H_3O^+ \] ### Step 3: Define the Hydrolysis Constant The hydrolysis constant \( K_h \) can be expressed in terms of the concentrations of the products and reactants at equilibrium: \[ K_h = \frac{[NH_3][H_3O^+]}{[NH_4^+]} \] ### Step 4: Relate Hydrolysis Constant to \( K_b \) The relationship between the hydrolysis constant \( K_h \) and the base dissociation constant \( K_b \) for the weak base \( NH_3 \) is given by: \[ K_h = \frac{K_w}{K_b} \] where \( K_w \) is the ion product of water. ### Step 5: Express Degree of Hydrolysis \( \alpha \) The degree of hydrolysis \( \alpha \) is defined as the fraction of the salt that has undergone hydrolysis. For a salt of a weak base, the degree of hydrolysis can be expressed as: \[ \alpha = \frac{K_w}{K_b \cdot C} \] where \( C \) is the concentration of the salt. ### Step 6: Final Relationship From the above equations, we can rearrange to find the relationship between \( K_b \) and \( \alpha \): \[ K_b = \frac{K_w}{\alpha \cdot C} \] ### Conclusion Thus, the correct relationship between the hydrolysis constant \( K_b \) and the degree of hydrolysis \( \alpha \) is: \[ K_b \propto \frac{K_w}{\alpha \cdot C} \]

To determine the correct relationship between the hydrolysis constant \( K_b \) and the degree of hydrolysis \( \alpha \), we can follow these steps: ### Step 1: Understand Hydrolysis Hydrolysis is a reaction involving the reaction of a salt with water, resulting in the formation of an acid and a base. For example, when ammonium chloride (\( NH_4Cl \)) is dissolved in water, it undergoes hydrolysis to produce ammonium ions (\( NH_4^+ \)) and chloride ions (\( Cl^- \)). The chloride ion does not undergo hydrolysis because it comes from a strong acid (HCl). ### Step 2: Write the Hydrolysis Reaction For the hydrolysis of \( NH_4Cl \): \[ ...
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