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The pH of 0.05 M Ba(OH)(2) solution is...

The pH of 0.05 M Ba`(OH)_(2)` solution is

A

12

B

13

C

1

D

12.96

Text Solution

Verified by Experts

The correct Answer is:
B
`{:(Ba(OH)_(2),rarr,Ba^(+2)+,2OH^(-)),(,,0.05 M,2 xx 0.5 M):}`
`pOH = log.(1)/([OH^(-)]) = log.(1)/(0.1) = 1`
`pH = pOH = 14 , pH + 1 = 14, pH = 14 -1 = 13`.
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