The pH value of 0.1 M HCl is approximately 1. What will be the approximately pH value of 0.05 `MH_(2)SO_(4)`

Options

A. 0.05
B. 0.5
C. 1
D. 2

Explanation

To find the approximate pH value of 0.05 M H₂SO₄, we can follow these steps:

### Step 1: Understand the dissociation of H₂SO₄
H₂SO₄ (sulfuric acid) is a strong acid that completely dissociates in water. The dissociation can be represented as:
\[ \text{H}_2\text{SO}_4 \rightarrow 2\text{H}^+ + \text{SO}_4^{2-} \]

### Step 2: Calculate the concentration of H⁺ ions
Since 1 mole of H₂SO₄ produces 2 moles of H⁺ ions, the concentration of H⁺ ions from 0.05 M H₂SO₄ will be:
\[ \text{Concentration of H}^+ = 2 \times 0.05 \, \text{M} = 0.1 \, \text{M} \]

### Step 3: Calculate the pH
The pH is calculated using the formula:
\[ \text{pH} = -\log[\text{H}^+] \]
Substituting the concentration of H⁺ ions:
\[ \text{pH} = -\log(0.1) \]

### Step 4: Simplify the logarithm
Using the properties of logarithms:
\[ \text{pH} = -(-1) = 1 \]

### Conclusion
Thus, the approximate pH value of 0.05 M H₂SO₄ is 1.

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