The dissociation constant of a substitut...

The dissociation constant of a substituted benzoic acid at `25^(@)C` is `1.0xx10^(-4)`. The `pH` of `0.01M` solution of its sodium salt is

Verified by Experts

The correct Answer is:

8

Given `K_(a) = 10^(-4), p_(a) = 4, C = 0.01 M`
`pH = 7 + (1)/(2) pK_(a) + (1)/(2)log C = 7 + (1)/(2) (4) + (1)/(2)(-2) = 8`.

Similar Questions

Explore conceptually related problems

The dissociation constant of a substituted benzoic acid at 25^(@)C is 1.0 xx 10^(-4) . The pH of 0.01M solution of its salt is :

The dissociation constant of a substitude benzoic acid at 25^(@)C is 1.0xx10^(-4) . The pH of a 0.01M solution of its sodium salt is

The dissociation constant of a substitued benzoic acid at 25^(@)C is 1.0 xx 10^(-1) . Find the pH of a 0.01M solution of its sodium salt.

The dissociation constant of a weak monobasic acid K_(a) is 1xx 10^(-5) . The pH of 0.1 M of that acid would be

The acid dissociation constant K_(a) of acetic acid is 1.74 xx 10^(-5) at 298 K. The pH of a solution of 0.1 M acetic acid is