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The work done during the expanision of a...

The work done during the expanision of a gas from a volume of `4 dm^(3)` to `6 dm^(3)` against a constant external pressure of 3 atm is (1 L atm = 101.32 J)

A

`+ 304 J`

B

`- 304 J`

C

`- 6 J`

D

`-608 J`

Text Solution

Verified by Experts

The correct Answer is:
D
`W=-pDeltaV, W=-3xx(6-4)`
`W=-6xx101.32(therefore "1 L atm=101.32 J")`
W=-608 J
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