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The standard enthalpy of formation of H(...

The standard enthalpy of formation of `H_(2)(g)` and `Cl_(2)(g)` and `HCl(g)` are `218 kJ//mol`, `121.88 kJ//mol` and `-93.31 kJ//mol` respectively. Calculate standard enthalpy change in `kJ` for
`(1)/(2)H_(2)(g)+(1)/(2)Cl_(2)(g)toHCl(g)`

A

`+431.99`

B

`-262.14`

C

`-431.99`

D

`+247.37`

Text Solution

Verified by Experts

The correct Answer is:
B
`Delta_(r)H=DeltaH_("products")-DeltaH_("reactants")`
`=-92.3-[(218)/(2)+(121.68)/(2)]=-92.3-[109+60.84]`
`=-262.14 kJ//mol`.
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