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Consider the reaction, N(2) + 3H(2) rarr...

Consider the reaction, `N_(2) + 3H_(2) rarr 2NH_(3)` carried out at constant temperature and pressure. If `Delta H and Delta U` are the enthalpy and internal energy changes for the reaction, which of the following expressions is true?

A

`DeltaH = 0`

B

`DeltaH = DeltaU`

C

`DeltaH lt DeltaU`

D

`DeltaH gt DeltaU`

Text Solution

Verified by Experts

The correct Answer is:
C
At constant P or T
`DeltaH=DeltaU+DeltanRTimplies Deltan=n_(p)-n_(R)=2-4=-2`
`therefore DeltaHltDeltaU`.
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