When 5 g of sulphur is burnt to `SO_(2)`, 46 kJ of heat is liberated. What is the enthalpy of formation of sulphur dioxide?

Options

A. `+ 147.2 kJ`
B. `- 147.2 kJ`
C. `- 294.4 kJ`
D. `+ 294.4 kJ`

Answer

C

Explanation

`S+O_(2)rarrSO_(2), DeltaH_(f)=-4.6 kJ`
`because` 0.5 gm of sulphur on burning produce 1 gm of `SO_(2)`
`therefore` 32 gm of sulphur on burning produce 64 gm of `SO_(2)`
`therefore DeltaH=(-4.6 kJ)xx64=-294.4 kJ`