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The formation of water from H(2)(g) and ...

The formation of water from `H_(2)(g)` and `O_(2)(g)` is an exothermic process because :

A

The chemical energy of `H_(2)(g)` and `O_(2)(g)` is more than that of water

B

The chemical energy of `H_(2)(g)` and `O_(2)(g)` is less than that of water

C

Not dependent on energy

D

The temperature of `H_(2)(g)` and `O_(2)(g)` is more than that of water

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The correct Answer is:
A
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The formation of the oxide ion O_((g))^(2-) requires first an exothermic and then an endothermic step as shown below. O_((g)) +e^(-) = O_((g))^(-) DeltaH^(@) =- 142 kJ mol^(-1) O_((g))^(-) + e^(-) = O_((g))^(2-) DeltaH^(@) = 844 kJ mol^(-1) This is because of :

The formation of the oxide ion O_(g)^(2-) requires first an exothermic and then an endothermic step as shown below: O_(g)+e^(-) rarr O_(g)^(-) , DeltaH=-142 kJ mol^(-1) O(g)+e rarr O_(g)^(2-) , DeltaH=844kJ mol^(-1) This is because:

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