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The heat of atomisation of PH(3(g)) is 2...

The heat of atomisation of `PH_(3(g))` is `228kcal mol^(-1)` and that of `P_(2)H_(4)` is `355kcal mol^(-1)`. Calculate the average bond energy of `P-P` bond.

A

102 k cal `mol^(-1)`

B

51 k cal `mol^(-1)`

C

26 k cal `mol^(-1)`

D

204 k cal `mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
Bond dissociation energy of `PH_(3)(g)`
= 228 k cal `mol^(-1)`
F - H bond energy `=(228)/(3)=76 " k cal mol"^(-1)`

Bond energy of 4(P-H)+(P-P)
`=355 k cal mol^(-1)`
or `4xx76+(P-P)=355k cal mol^(-1)implies51 k cal mol^(-1)`
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