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For vaporization of water at 1 atmospher...

For vaporization of water at 1 atmospheric pressure the values of `DeltaH` and `DeltaS` are `40.63KJmol^(-1)` and `108JK^(-1)mol^(-1)` , respectively. The temperature when Gibbs energy change `(DeltaG)` for this transformation will be zero is

A

273.4 K

B

393.4 K

C

373.4 K

D

293.4 K

Text Solution

Verified by Experts

The correct Answer is:
C
`DeltaG=DeltaH-TDeltaS`
`DeltaG=0`
`DeltaH=TDeltaS`,
`T=(40.63xx10^(3))/(108.8)=373.4 K`.
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