One molee of methanol when burnt in `O_(2)`, gives out 723 kJ `mol^(-1)` of heat. If one mole of `O_(2)` is used, what will be the amount of heat evovled?

Options

A. 723 kJ
B. 924 kJ
C. 482 kJ
D. 241 kJ

Answer

C

Explanation

`CH_(3)OH(l)+(3)/(2)O_(2)(g)rarrCO_(2)(g)+2H_(2)O(l) DeltaH=-723 kJ`
By burning with `(3)/(2)O_(2)(g)` heat evolved =-723 kJ
`therefore` By burning with 1 mole `O_(2)(g)=(-723xx2)/(3)=-482 kJ`.