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The rate of the reaction A rarr products...

The rate of the reaction `A rarr` products, at the initial concentration of `3.24 xx 10^(-2)M` is nine times its rate at another initial concentration of `1.2 xx 10^(-3)M`. The order of reaction is

A

`(1)/(2)`

B

`(3)/(4)`

C

`(3)/(2)`

D

`(2)/(3)`

Text Solution

Verified by Experts

The correct Answer is:
d
9r = `k (3.24 xx 10^(-2))^(alpha ) " " …. (i)`
`r = k(1.2 xx 10^(-3))^(alpha) " " …. (ii)`
Divide eq. (i) by (ii)
`(9r)/(r) = (k(3.24 xx 10^(-2))^(alpha))/(k (1.2 xx 10^(-3))^(alpha)) implies 3^(2) = 3^(3alpha)`
`therefore alpha = (2)/(3)`.
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