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If the activation enery for the forward ...

If the activation enery for the forward reaction is `150 "kJ mol"^(-1)` and that of the reverse reaction is `260 "kJ mol"^(-1)`. What is the ethalpy change for the reaction ?

A

410 kJ `mol^(-1)`

B

`-110kJ mol^(-1)`

C

110 kJ `mol^(-1)`

D

`-410 kJ mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
b
For a reversible reaction ,
`Delta H = E_(a)` (forward) `- E_(a)` (backward)
`DeltaH = 150 - 260 = -110 kJ mol^(-1)`.
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