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The rate constant for the reaction, 2N(2...

The rate constant for the reaction, `2N_(2)O_(5) rarr 4NO_(2) + O_(2)` is `3.0 xx 10^(-5) s^(-1)`. If the rate is `2.40 xx 10^(-5) mol L^(-1) s^(-1)`, then the initial concentration of `N_(2)O_(5)` (in `mol L^(-1)`) is

A

`1.4`

B

1.2

C

`0.04`

D

`0.8`

Text Solution

Verified by Experts

The correct Answer is:
d
Rate = `k (N_(2)O_(5))` hence `2.4 xx 10^(-5) = 3.0 xx 10^(-5) (N_(2)O_(5))`
or `(N_(2)O_(5)) = 0.8` mol `l^(-1)`
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