Amongest the following compounds, the one which would not form a white precipitate with ammonical silver nitrate solution is

Options

A. `HC -= CH`
B. `H_(3)C - C -= C - CH_(3)`
C. `H_(3)C - C = CH`
D. `CH_(3)CH_(2)CH_(2)C -= CH`

Explanation

To solve the question regarding which compound does not form a white precipitate with ammonical silver nitrate solution, we can follow these steps:

### Step 1: Understand the Reaction
Ammonical silver nitrate (AgNO3 in ammonia) is known to react with terminal alkynes to form a white precipitate of silver acetylide. Non-terminal alkynes do not react in the same way and do not form this precipitate.

### Step 2: Identify the Types of Alkynes
- **Terminal Alkynes**: These have a triple bond at the end of the carbon chain (e.g., ethyne or propyne).
- **Non-terminal Alkynes**: These have a triple bond somewhere in the middle of the carbon chain (e.g., butyne).

### Step 3: Analyze the Given Compounds
Assuming the question provides a list of compounds, we need to categorize each compound as either a terminal alkyne or a non-terminal alkyne.

### Step 4: Determine the Precipitate Formation
- For each terminal alkyne, a white precipitate will form when treated with ammonical silver nitrate.
- For each non-terminal alkyne, no white precipitate will form.

### Step 5: Identify the Correct Answer
From the analysis, the compound that is a non-terminal alkyne will be the one that does not form a white precipitate with ammonical silver nitrate.

### Conclusion
The compound that does not form a white precipitate with ammonical silver nitrate is the non-terminal alkyne (option 2).

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