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Which of the following compounds shows t...

Which of the following compounds shows tautomerism

A

HCHO

B

`CH_(3)CHO`

C

`CH_(3)COCH_(3)`

D

HCOOH

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given compounds shows tautomerism, we need to evaluate each option based on the necessary conditions for tautomerism. Tautomerism typically involves the presence of a functional group that can undergo a shift of a hydrogen atom and a rearrangement of bonds, often between a keto form and an enol form. The key requirements for tautomerism are: 1. The presence of a functional group that can undergo tautomerization (typically a carbonyl group). 2. The presence of an alpha hydrogen atom (H) on the carbon adjacent to the carbonyl carbon. Now, let's analyze each compound: ### Step 1: Analyze Formaldehyde (HCHO) - **Structure**: HCHO has no alpha carbon because it is an aldehyde with only one carbon atom. - **Conclusion**: Since there is no alpha hydrogen, formaldehyde does not show tautomerism. ### Step 2: Analyze Acetaldehyde (CH3CHO) - **Structure**: Acetaldehyde has the structure CH3CHO. The carbonyl carbon (C=O) is adjacent to the methyl group (CH3). - **Alpha Hydrogen**: The methyl group has three alpha hydrogens. - **Conclusion**: Acetaldehyde can undergo tautomerism, as it meets both conditions. ### Step 3: Analyze Acetone (CH3COCH3) - **Structure**: Acetone has the structure CH3COCH3. The carbonyl carbon is flanked by two methyl groups. - **Alpha Hydrogen**: Each methyl group has three alpha hydrogens. - **Conclusion**: Acetone can also undergo tautomerism, satisfying the necessary conditions. ### Step 4: Analyze Formic Acid (HCOOH) - **Structure**: Formic acid has the structure HCOOH. Similar to formaldehyde, it has no alpha carbon. - **Conclusion**: Since there is no alpha hydrogen, formic acid does not show tautomerism. ### Final Conclusion The compounds that show tautomerism from the given options are: - Acetaldehyde (CH3CHO) - Acetone (CH3COCH3) ### Summary of Results: - **Formaldehyde**: Does not show tautomerism. - **Acetaldehyde**: Shows tautomerism. - **Acetone**: Shows tautomerism. - **Formic Acid**: Does not show tautomerism.

To determine which of the given compounds shows tautomerism, we need to evaluate each option based on the necessary conditions for tautomerism. Tautomerism typically involves the presence of a functional group that can undergo a shift of a hydrogen atom and a rearrangement of bonds, often between a keto form and an enol form. The key requirements for tautomerism are: 1. The presence of a functional group that can undergo tautomerization (typically a carbonyl group). 2. The presence of an alpha hydrogen atom (H) on the carbon adjacent to the carbonyl carbon. Now, let's analyze each compound: ### Step 1: Analyze Formaldehyde (HCHO) ...
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