The IUPAC name of this compound
`{:(CH_(3)-CH-CH_(2)-CH-COOH),(" |"" |"),(" "C_(2)H_(5)" "CH_(3)):}`

Options

A. 2,2-diethyl pentanoic acid
B. 2, 4-dimethyl hexanoic acid
C. 2-methyl-4-ethyl pentanoic acid
D. 4-ethyl-2-methyl pentanoic acid

Explanation

To determine the IUPAC name of the given compound, we will follow these steps:

### Step 1: Identify the Functional Group
The compound contains a carboxylic acid functional group (-COOH). In IUPAC nomenclature, the carboxylic acid group takes priority and is given the lowest possible number.

### Step 2: Determine the Longest Carbon Chain
We need to identify the longest continuous carbon chain that includes the carboxylic acid group. In this case, the longest chain consists of 6 carbon atoms.

### Step 3: Number the Carbon Chain
Number the carbon chain starting from the end nearest to the carboxylic acid group:
1. Carboxylic acid (C1)
2. C2
3. C3
4. C4
5. C5
6. C6

### Step 4: Identify and Name Substituents
From the structure, we can see that there are two methyl groups (-CH₃) attached to the carbon chain:
- One methyl group is on carbon 2
- Another methyl group is on carbon 4

### Step 5: Combine the Names
Now we can combine the names:
- The base name for a 6-carbon chain is "hexane."
- Since there are two methyl groups, we use "dimethyl" to indicate their presence.
- The suffix for the carboxylic acid is "oic acid."

### Step 6: Finalize the IUPAC Name
Putting it all together, we have:
- The substituents (dimethyl) come first, followed by the base name (hex) and the functional group suffix (oic acid).
- Therefore, the final IUPAC name is **2,4-dimethylhexanoic acid**.

### Summary of the IUPAC Name
The IUPAC name of the compound is **2,4-dimethylhexanoic acid**.

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