The bond between carbon atom (1) and carbon atom (2) in compound `N-=underset(1)(C)-underset(2)(CH)=CH_(2)`, involves the hybridization as

Options

A. `sp^(2)` and `sp^(2)`
B. `sp^(3)` and sp
C. sp and `sp^(2)`
D. sp and sp

Explanation

To determine the hybridization of the carbon atoms in the compound N≡C-CH=CH2, we will analyze the bonding and geometry around each carbon atom.

### Step-by-Step Solution:

1. **Identify the Structure**: The compound is N≡C-CH=CH2. This indicates that there is a triple bond between the nitrogen (N) and the first carbon (C1), a single bond between C1 and the second carbon (C2), and a double bond between C2 and the third carbon (C3).

2. **Analyze Carbon Atom 1 (C1)**:
- C1 is involved in a triple bond with nitrogen (N) and a single bond with C2.
- A triple bond consists of one sigma (σ) bond and two pi (π) bonds. Therefore, C1 has:
- 1 σ bond (with N)
- 1 σ bond (with C2)
- Total σ bonds = 2
- Since C1 has 2 σ bonds, the hybridization can be determined using the formula:
- Hybridization = number of σ bonds = 2 → sp hybridization.

3. **Analyze Carbon Atom 2 (C2)**:
- C2 is bonded to C1 with a single bond and to C3 with a double bond.
- The double bond consists of one σ bond and one π bond. Therefore, C2 has:
- 1 σ bond (with C1)
- 1 σ bond (with C3)
- 1 σ bond (with one hydrogen atom)
- Total σ bonds = 3
- Since C2 has 3 σ bonds, the hybridization can be determined using the formula:
- Hybridization = number of σ bonds = 3 → sp² hybridization.

4. **Conclusion**:
- The hybridization of C1 is sp, and the hybridization of C2 is sp².

### Final Answer:
The bond between carbon atom (1) and carbon atom (2) in the compound N≡C-CH=CH2 involves the hybridization as sp (for C1) and sp² (for C2).