The number of isomers of `C_(6)H_(14)` is

Options

A. 4
B. 5
C. 6
D. 7

Answer

B

Explanation

(i) `CH_(3)-CH_(2)-CH_(2)-CH_(2)-CH_(2)-CH_(3)`
(ii) `{:(CH_(3)-CH-CH_(2)-CH_(2)-CH_(3)),(" |"),(" "CH_(3)):}`
(iii) `{:(CH_(3)-CH-CH-CH_(3)),(" |"" |"),(" "CH_(3)" "CH_(3)):}`
(iv) `{:(" "CH_(3)),(" |"),(CH_(3)-C-CH_(2)-CH_(3)),(" |"),(" "CH_(3)):}`
(v) `{:(CH_(3)-CH_(2)-CH-CH_(2)-CH_(3)),(" |"),(" "CH_(3)):}`