Carbon atoms in the compound `(CN)_(4)C_(2)` are

Options

A. sp hybridized
B. `sp^(2)` hybridized
C. sp & `sp^(2)` hybridized
D. sp, `sp^(2)` & `sp^(3)` hybridized

Explanation

To determine the types of carbon atoms in the compound \( \text{CN}_4\text{C}_2 \), we can follow these steps:

### Step 1: Identify the Structure of the Compound
The compound \( \text{CN}_4\text{C}_2 \) is known as tetra-sinoethene. This indicates that it has a specific arrangement of carbon and nitrogen atoms.

### Step 2: Analyze the Carbon Atoms
In the formula \( \text{CN}_4\text{C}_2 \):
- There are 2 carbon atoms (C) in the compound.
- The presence of \( \text{N}_4 \) indicates that there are four nitrogen atoms bonded to these carbon atoms.

### Step 3: Determine the Hybridization of Carbon Atoms
- The structure of tetra-sinoethene includes a carbon-carbon double bond (C=C) and carbon-nitrogen triple bonds (C≡N).
- The carbon atoms involved in the double bond (C=C) will have a hybridization of \( sp^2 \).
- The carbon atoms involved in the triple bonds (C≡N) will also have a hybridization of \( sp \).

### Step 4: Conclude the Types of Carbon Atoms
- In tetra-sinoethene, we have:
- One carbon atom involved in a double bond (C=C) which is \( sp^2 \) hybridized.
- One carbon atom involved in triple bonds (C≡N) which is \( sp \) hybridized.

Thus, we have two types of carbon atoms: one \( sp^2 \) hybridized and one \( sp \) hybridized.

### Final Answer
The carbon atoms in the compound \( \text{CN}_4\text{C}_2 \) are of two types: one \( sp^2 \) hybridized and one \( sp \) hybridized.

---