Methyl cyanide on dilution with HCl produces

Options

A. `CH_(3)COOH`
B. `HCOOH`
C. `CH_(3)-CO-CH_(3)`
D. `CH_(3)-CHO`

Answer

To solve the question "Methyl cyanide on dilution with HCl produces," we will follow these steps:

### Step 1: Identify Methyl Cyanide
Methyl cyanide, also known as acetonitrile, has the chemical formula CH₃CN. It consists of a methyl group (CH₃) attached to a cyano group (CN).

### Step 2: Understand the Reaction with Dilute HCl
When methyl cyanide is treated with dilute hydrochloric acid (HCl), it undergoes hydrolysis. Dilute HCl means that water is present along with HCl, which provides H⁺ ions (or H₃O⁺ ions) that facilitate the hydrolysis reaction.

### Step 3: Write the Hydrolysis Reaction
The hydrolysis of methyl cyanide can be represented as follows:
\[ \text{CH}_3\text{CN} + 2 \text{H}_2\text{O} \xrightarrow{\text{HCl}} \text{CH}_3\text{COOH} + \text{NH}_3 \]
In this reaction, methyl cyanide reacts with water in the presence of HCl to produce acetic acid (CH₃COOH) and ammonia (NH₃).

### Step 4: Identify the Products
From the hydrolysis reaction, we can see that the primary product is acetic acid (CH₃COOH), and ammonia (NH₃) is also produced as a byproduct.

### Conclusion
Thus, the final answer to the question is that methyl cyanide on dilution with HCl produces acetic acid and ammonia.

### Summary of the Answer
Methyl cyanide (CH₃CN) on dilution with HCl produces acetic acid (CH₃COOH) and ammonia (NH₃).

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