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An organic compound containing C,H and N...

An organic compound containing C,H and N gave the following analysis
C=40 %,H=13.33 %,N=46.67 %
What would be its empirical formula ?

A

`C_(2)H_(7)N_(2)`

B

`CH_(5)N`

C

`CH_(4)N`

D

`C_(2)H_(7)N`

Text Solution

Verified by Experts

The correct Answer is:
C
`{:("Element"," NO. of moles"," Simple ratio"),(C 40%,40//12=3.33,1),(H13.33%,13.33//1=13.33,4),(N46.67%,46.67//14=3.33,1):}`
thus formula `CH_(4)N`.
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