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In Duma's method for estimation of nitro...

In Duma's method for estimation of nitrogen. `0.25 g `of an organic compound gave `40mL` of nitrogen collected at `300K` temperature of `725 mm` pressure. If the aqueous tension at `300K` is `25 mm`, the percentage of nitrogen in the compound is

A

`18.20`

B

`16.76`

C

`15.76`

D

`17.36`

Text Solution

Verified by Experts

The correct Answer is:
B
Mass of organic comp. `= 0.25 g`
`V_(1) = 40 ml`
`T_(1) = 300 K`
`P_(1) = 725 - 25 = 700 nm` of `Hg`
`(P_(1)V_(1))/(T_(1)) = (P_(2)V_(2))/(T_(2))`
`V_(2) = (700xx 40 xx 273)/(300 xx 760) = 323.52 ml`
`%` of `N = (28 xx V xx 100)/(22400 xx " mass of org.com")`
`= (28 xx 33.52 xx 100)/(22400 xx 0.25) = 16.76`
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