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If a compound on analysis was found to c...

If a compound on analysis was found to contain `C=18.5%, h=1.55%,Cl=55.04%` and `O=25.81%`, then its empirical formul is

A

`CHClO`

B

`CH_(3)ClO`

C

`C_(2)H_(2)Ocl`

D

`ClCH_(2)O`

Text Solution

Verified by Experts

The correct Answer is:
A
`{:("Element"," NO. of moles"," Simple ratio"),(C 18.5%,18.5//12=1.54,1),(H1.55%,1.55//1=1.55,1),(Cl55.04%,55.04//35.5=1.55,1),(O24.81%,24.81//16=1.55,1):}`
Hence, formula `= CHClO`.
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