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A compound (80 g) on analysis gave C=24 ...

A compound `(80 g)` on analysis gave `C=24 g, H=4 g, O=32 g`. Its empirical formula is

A

`C_(2)H_(4)O_(2)`

B

`C_(2)H_(2)O`

C

`CH_(2)O_(2)`

D

`CH_(2)O`

Text Solution

Verified by Experts

The correct Answer is:
D
`{:("Element"," NO. of moles"," Simple ratio"),(C =24,24//12=2,1),(H=4,4//1=4,2),(O=32,32//16,1):}`
Therefore `CH_(2)O`.
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