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An organic compound containing C = 38.8%...

An organic compound containing `C = 38.8%, H = 16%` and `n = 45.2%`. Empirical formula of the compound is

A

`CH_(3)NH_(2)`

B

`CH_(3)CN`

C

`C_(2)H_(5)CN`

D

`CH_(2)(NH)_(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`{:("Element"," NO. of moles"," Simple ratio"),(C=38.8,38.8//12=3.2,1),(H=16,16//1=16,5),(N=45.2,45.2//14=3.2,1):}`
Therefore, Empirical formula `= CH_(5)N` or `CH_(3)NH_(2)`.
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