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An organic compound on analysis gave C=...

An organic compound on analysis gave `C=48 g,H=8g` and `N=56 g.` Volume of `1.0 g` of the compound was foud to be `200ml` at `NTP.` Molecular formula of the compound is

A

`C_(4)H_(8)N_(4)`

B

`C_(2)H_(4)N_(2)`

C

`C_(12)H_(24)N_(12)`

D

`C_(16)H_(32)N_(16)`

Text Solution

Verified by Experts

The correct Answer is:
A
`{:("Element",%," NO. of moles"," Simple ratio"),(C,48,48//12=4,1),(H,8,8//1=8,2),(N,56,56//14=4,1):}`
Empirical formula ` = CH_(2)N`
Empirical formula mass `= 28`
Now, `200ml` of compound `= 1 gm`
`22400 ml` of compound `1/200 xx 22400 = 112`
`n '(" Mol.mass")/(" Emp.formula mass") = 112/28 = 4`
Therefore, molecular formula `= (CH_(2)N)_(4) = C_(4)H_(8)N_(4)`.
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