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0.0833 mol of carbohydrate of empirical ...

`0.0833 `mol of carbohydrate of empirical formula `CH_(2)O` contain `1 g ` of hydrogen. The molecular formula of the carbohydrate is

A

`C_(5)H_(10)O_(5)`

B

`C_(3)H_(4)O_(3)`

C

`C_(12)H_(22)O_(11)`

D

`C_(6)H_(12)O_(6)`

Text Solution

Verified by Experts

The correct Answer is:
D
`:' 0.0833` mole carbohydrate has hydrogen `= 1g`
`:.` 1 mole carbohydrate has hydrogen
`= 1/(0.0833) =12g`
Empirical Formula `(CH_(2)O)` has hydrogen `= 2g`
Hence ` n = (12)/(2)= 6`
Hence molecular formula of carbohydrate `= 2g`
Hence `n = 12/2 =6`
Hence molecular formula of carbohydrate `= (CH_(2)O)_(6)`
`= C_(6)H_(12)O_(6)`.
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