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An organic compound on analysis gav...

An organic compound on analysis gave the following results : `C=54.5% ,O= 36.4 % H=9.1 % ` . The empirical formula of the compound is ____.

A

`C_(2)H_(4)`

B

`C_(3)H_(4)O`

C

`C_(3)H_(4)O`

D

`C_(4)H_(8)O`

Text Solution

Verified by Experts

The correct Answer is:
B
`{:("Element"," No. of moles"," Simple Ratio"),(C=54.5,54.5//12=4.54,=2(2.2)),(H=9.1,9.1//1=9.1,=4(4.5)),(O=36.4,36.4//16=2.27,=1(1)):}`
Hence `C_(2)H_(4)O`.
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