Home
Class 12
CHEMISTRY
An organic compound contain 54% carbon. ...

An organic compound contain `54%` carbon. It could be

A

Ethanol

B

Dimethyl ether

C

diethyl ether

D

Acetic acid

Text Solution

AI Generated Solution

The correct Answer is:
To determine which organic compound contains 54% carbon, we will calculate the percentage of carbon in each of the given compounds. Here’s a step-by-step breakdown of the solution: ### Step 1: Identify the Compounds The compounds given in the question are: 1. Ethanol (C2H5OH) 2. Dimethyl ether (C2H6O) 3. Diethyl ether (C4H10O) 4. Acetic acid (C2H4O2) ### Step 2: Calculate the Molecular Weight of Each Compound - **Ethanol (C2H5OH)**: - Carbon (C): 2 × 12 = 24 g/mol - Hydrogen (H): 6 × 1 = 6 g/mol - Oxygen (O): 1 × 16 = 16 g/mol - Total Molecular Weight = 24 + 6 + 16 = 46 g/mol - **Dimethyl ether (C2H6O)**: - Carbon (C): 2 × 12 = 24 g/mol - Hydrogen (H): 6 × 1 = 6 g/mol - Oxygen (O): 1 × 16 = 16 g/mol - Total Molecular Weight = 24 + 6 + 16 = 46 g/mol - **Diethyl ether (C4H10O)**: - Carbon (C): 4 × 12 = 48 g/mol - Hydrogen (H): 10 × 1 = 10 g/mol - Oxygen (O): 1 × 16 = 16 g/mol - Total Molecular Weight = 48 + 10 + 16 = 74 g/mol - **Acetic acid (C2H4O2)**: - Carbon (C): 2 × 12 = 24 g/mol - Hydrogen (H): 4 × 1 = 4 g/mol - Oxygen (O): 2 × 16 = 32 g/mol - Total Molecular Weight = 24 + 4 + 32 = 60 g/mol ### Step 3: Calculate the Percentage of Carbon in Each Compound The formula for calculating the percentage of carbon is: \[ \text{Percentage of Carbon} = \left( \frac{\text{Total Weight of Carbon}}{\text{Total Molecular Weight}} \right) \times 100 \] - **Ethanol**: \[ \text{Percentage of Carbon} = \left( \frac{24}{46} \right) \times 100 \approx 52.17\% \] - **Dimethyl ether**: \[ \text{Percentage of Carbon} = \left( \frac{24}{46} \right) \times 100 \approx 52.17\% \] - **Diethyl ether**: \[ \text{Percentage of Carbon} = \left( \frac{48}{74} \right) \times 100 \approx 64.86\% \] - **Acetic acid**: \[ \text{Percentage of Carbon} = \left( \frac{24}{60} \right) \times 100 \approx 40\% \] ### Step 4: Compare the Results From the calculations: - Ethanol: 52.17% - Dimethyl ether: 52.17% - Diethyl ether: 64.86% - Acetic acid: 40% ### Conclusion The compounds that are closest to containing 54% carbon are **Ethanol** and **Dimethyl ether**, both of which have approximately 52.17% carbon. ### Final Answer The organic compound that contains approximately 54% carbon could be **Ethanol** and **Dimethyl ether**. ---

To determine which organic compound contains 54% carbon, we will calculate the percentage of carbon in each of the given compounds. Here’s a step-by-step breakdown of the solution: ### Step 1: Identify the Compounds The compounds given in the question are: 1. Ethanol (C2H5OH) 2. Dimethyl ether (C2H6O) 3. Diethyl ether (C4H10O) 4. Acetic acid (C2H4O2) ...
Promotional Banner

Topper's Solved these Questions

  • Practical Organic Chemistry

    ERRORLESS |Exercise JEE Ssection (Only one choice correct answer)|22 Videos
  • ORES, MINERALS AND METALLURGICAL EXTRACTION

    ERRORLESS |Exercise JEE ANSWER TPYE QUESTION (JEE Advanced) 2018) Numeric answer type question|1 Videos
  • S AND P BLOCK ELEMENTS

    ERRORLESS |Exercise JEE Section (JEE advanced ) 2018(Numeric answer type question)|1 Videos

Similar Questions

Explore conceptually related problems

An organic compund contains 52% carbon. If could be

An organic compound contains 40% carbons atom 6.67% hydrogen atoms and remaining oxygen atoms by mass. The empirical formula will be-

An organic compound contains about 7.8% carbon. Its acidic sodium extract gives a white precipitate with AgNO3. This precipitate is soluble in the excess of ammonia. The compound is:

An organic compound contains 49.3 % carbon,6.84 % hydrogen and its vapour density is 73 Molecular formula of the compound is

An organic compound contains 49.3% carbon. 6.84% hydrogen and its vapour density is 73. Molecular formula of compound is

An organic compound contains 49.3% carbon 6.84% hydrogen and its vapour density is 73 . Molecular formula of the compund is

An organic compound containd 78%(by wt.) carbon and remaining % of hydrogen. The right option for the emprical formula of this compound is: