Pick out the correct statement with respect to `[Mn(CN)_(6)]^(3-)`:

Options

A. It is `sp^(3)d^(2)` hybridised and tetrahedral
B. It is `d^(2)sp^(3)` hybridised and cotahedral
C. It is `dsp^(2)` hybridised and square planar
D. It is `sp^(3)d^(2)` hybridised and octahedral

Answer

B

Explanation

`[Mn(CN)_(6)]^(3-)rarr `O.S. of Mn is `( +3)`
Coordination number `=6`