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The coordination number of Ni^(2+) is 4 ...

The coordination number of `Ni^(2+)` is 4
`NiCI_(2) + KCN` (excess) gives `A` (cyano complex)
`NiCI_(2)+conc.HCI` (excess) gives `B` (Chloro complex)
The `IUPAC` name of `A` and `B` are .

A

Potassium tetracyanonickelate (II), Potassium tetrachloronickelate (II).

B

Tetracyanopotassiumnickelate (II), tetrachloropotassiumnickelate (II)

C

Tetracyanonickel (II), tetrachloronickel (II)

D

Potassium tetracyanonickel (II), potassium tetrachloronickel (II)

Text Solution

Verified by Experts

The correct Answer is:
A
(i) `NiCl_(2)+underset("Excess")(4KCN) rarr underset("(Cyano complex)")underset("('B')")underset("Potassium tetracyano nickelate (II)")(K_(2)[Ni(CN)_(4)]+2KCl)`
(ii) `K_(2)[Ni(CN)_(4)]+underset("Excess")(4HCl(conc.))rarr underset ("(Chloro complex)")underset("('B')")underset("Potassium tetrachloro nickelate (II)")(K_(2)[Ni(Cl)_(4)+4HCN))`
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