_______is formed when potassium iodide is heated with conc. `H_(2)SO_(4)`

Options

A. `HI`
B. `I_(2)`
C. `HIO_(3)`
D. `KIO_(3)`

Explanation

To determine what is formed when potassium iodide (KI) is heated with concentrated sulfuric acid (H2SO4), we can analyze the chemical reaction that occurs.

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactants in this reaction are potassium iodide (KI) and concentrated sulfuric acid (H2SO4).

2. **Understanding the Reaction**: When potassium iodide is heated with concentrated sulfuric acid, a redox reaction occurs. The iodide ions (I⁻) in KI are oxidized to iodine (I2), while the sulfuric acid is reduced.

3. **Write the Balanced Chemical Equation**:
The balanced chemical equation for the reaction is:
\[ 8 \text{KI} + 5 \text{H}_2\text{SO}_4 \rightarrow 4 \text{I}_2 + 4 \text{K}_2\text{SO}_4 + 4 \text{H}_2\text{O} + \text{H}_2\text{S} \]

4. **Identify the Products**: From the balanced equation, we can see that the products formed are:
- Iodine (I2)
- Potassium sulfate (K2SO4)
- Water (H2O)
- Hydrogen sulfide (H2S)

5. **Conclusion**: The main product of interest when potassium iodide is heated with concentrated sulfuric acid is iodine (I2).

### Final Answer:
**Iodine (I2)** is formed when potassium iodide is heated with concentrated sulfuric acid.