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When H(2)S gas is passed into a certain ...

When `H_(2)S` gas is passed into a certain solution, it reacts to form a white precipitate. The solution referred to contains ions of

A

Lead

B

Zinc

C

Copper

D

Nickel

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The correct Answer is:
To determine which ions in the solution react with hydrogen sulfide (H₂S) to form a white precipitate, we can follow these steps: ### Step 1: Identify the nature of H₂S H₂S is a weak acid and a source of sulfide ions (S²⁻) when it dissolves in water. ### Step 2: Understand the reaction with metal ions When H₂S is passed into a solution containing metal ions, it can form precipitates with certain metal sulfides. The formation of a white precipitate indicates that the metal ions in the solution are likely to form insoluble sulfides. ### Step 3: Identify common metal ions that form white precipitates with sulfide Common metal ions that form white precipitates with sulfide ions include: - Lead (Pb²⁺) as lead(II) sulfide (PbS) - Barium (Ba²⁺) as barium sulfide (BaS) - Cadmium (Cd²⁺) as cadmium sulfide (CdS) ### Step 4: Determine the most likely candidate Among these, lead(II) sulfide (PbS) is often noted for its characteristic white precipitate when H₂S is introduced into a solution containing lead ions. ### Conclusion Thus, the solution referred to contains ions of **lead (Pb²⁺)**, which reacts with H₂S to form a white precipitate of lead(II) sulfide (PbS). ---

To determine which ions in the solution react with hydrogen sulfide (H₂S) to form a white precipitate, we can follow these steps: ### Step 1: Identify the nature of H₂S H₂S is a weak acid and a source of sulfide ions (S²⁻) when it dissolves in water. ### Step 2: Understand the reaction with metal ions When H₂S is passed into a solution containing metal ions, it can form precipitates with certain metal sulfides. The formation of a white precipitate indicates that the metal ions in the solution are likely to form insoluble sulfides. ...
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