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H(2)S is passed through as acidified sol...

`H_(2)S` is passed through as acidified solution of Ag, Cu and Zn. Which forms precipitate

A

`Ag`

B

Zn

C

Cu

D

None of these

Text Solution

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The correct Answer is:
To determine which of the metals (Ag, Cu, Zn) forms a precipitate when H₂S is passed through an acidified solution, we need to consider the solubility of their sulfides in acidic conditions. ### Step-by-step Solution: 1. **Identify the Metals and Their Sulfides**: - Silver (Ag) forms silver sulfide (Ag₂S). - Copper (Cu) forms copper(I) sulfide (Cu₂S) and copper(II) sulfide (CuS). - Zinc (Zn) forms zinc sulfide (ZnS). 2. **Check the Solubility of Sulfides**: - Ag₂S: Silver sulfide is insoluble in water and precipitates out when H₂S is introduced. - CuS: Copper(II) sulfide is also insoluble in water and will precipitate out. However, Cu₂S is less common in acidic conditions. - ZnS: Zinc sulfide is generally soluble in acidic solutions, so it will not precipitate. 3. **Conclusion**: - When H₂S is passed through an acidified solution containing Ag, Cu, and Zn, the metals that will form precipitates are **Ag** (as Ag₂S) and **Cu** (as CuS). **Zn** does not form a precipitate. ### Final Answer: **Ag and Cu will form precipitates when H₂S is passed through an acidified solution containing Ag, Cu, and Zn.**

To determine which of the metals (Ag, Cu, Zn) forms a precipitate when H₂S is passed through an acidified solution, we need to consider the solubility of their sulfides in acidic conditions. ### Step-by-step Solution: 1. **Identify the Metals and Their Sulfides**: - Silver (Ag) forms silver sulfide (Ag₂S). - Copper (Cu) forms copper(I) sulfide (Cu₂S) and copper(II) sulfide (CuS). - Zinc (Zn) forms zinc sulfide (ZnS). ...
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