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In analysis of third contains of mixture...

In analysis of third contains of mixture analysis, solid `NH_(4)Cl` is added prior to `NH_(4)OH` for the following

A

Availability of `Cl^(-)` ions

B

Availability of `NH_(4)^(+)` ions

C

Complete dissociation of `NH_(4)OH`

D

Controlled dissociation of `NH_(4)OH`

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The correct Answer is:
To solve the question regarding the addition of solid \( NH_4Cl \) prior to \( NH_4OH \) in the analysis of a mixture, we can break down the process step by step: ### Step 1: Understanding the Components - **Identify the compounds**: We have \( NH_4Cl \) (ammonium chloride) and \( NH_4OH \) (ammonium hydroxide). - **Dissociation in solution**: - \( NH_4Cl \) dissociates into \( NH_4^+ \) and \( Cl^- \). - \( NH_4OH \) dissociates into \( NH_4^+ \) and \( OH^- \). ### Step 2: Effect of Adding \( NH_4Cl \) - When solid \( NH_4Cl \) is added to the solution, it increases the concentration of \( NH_4^+ \) ions in the solution. - The increased concentration of \( NH_4^+ \) will shift the equilibrium of the dissociation of \( NH_4OH \) according to Le Chatelier's Principle. ### Step 3: Shifting the Equilibrium - The dissociation of \( NH_4OH \) can be represented as: \[ NH_4OH \rightleftharpoons NH_4^+ + OH^- \] - With the addition of \( NH_4Cl \), the concentration of \( NH_4^+ \) increases, causing the equilibrium to shift to the left (backward direction). - This shift reduces the concentration of \( OH^- \) ions because they are being consumed to form \( NH_4OH \). ### Step 4: Implications for Precipitation - The decrease in \( OH^- \) concentration affects the solubility product constant (\( K_{sp} \)) of certain compounds that may precipitate in the presence of hydroxide ions. - By controlling the concentration of \( NH_4OH \) through the addition of \( NH_4Cl \), we can manage the precipitation of certain metal hydroxides that depend on \( OH^- \) concentration. ### Conclusion - The addition of solid \( NH_4Cl \) prior to \( NH_4OH \) helps control the concentration of \( NH_4OH \) and \( OH^- \) ions, which is crucial for the analysis of the third component in the mixture.
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