When `H_(2)S` gas is passed in a metal sulphate solution in presence of `NH_(4)OH`, a white precipitate is produced. The metal is identified as

Options

A. Zn
B. Fe
C. Pb
D. Hg

Explanation

To identify the metal in the given scenario, we need to analyze the reaction that occurs when hydrogen sulfide (H₂S) gas is passed through a metal sulfate solution in the presence of ammonium hydroxide (NH₄OH).

### Step-by-Step Solution:

1. **Understanding the Reaction**:
When H₂S is bubbled through a metal sulfate solution, it can react with metal ions present in the solution to form metal sulfides. The presence of NH₄OH (ammonium hydroxide) helps to maintain a basic environment which can influence the solubility of the metal sulfides formed.

2. **Identifying the Precipitate**:
The white precipitate formed indicates that a metal sulfide is produced. Common metal sulfides that are white in color include those of lead (PbS), barium (BaS), and others. However, in the context of metal sulfates and the conditions provided, we need to focus on the likely candidates.

3. **Common Metal Sulfates**:
The metal sulfate solutions that are typically tested in a laboratory setting include those of lead (Pb), barium (Ba), and others. When H₂S is passed through these solutions, we need to identify which metal sulfate produces a white precipitate.

4. **Reaction with H₂S**:
- For lead sulfate (PbSO₄), when H₂S is introduced, lead sulfide (PbS) is formed, which is black, not white.
- For barium sulfate (BaSO₄), barium sulfide (BaS) is formed, which is also not white.
- However, if we consider the presence of ammonium hydroxide, it can lead to the formation of a white precipitate of ammonium metal sulfide complexes.

5. **Conclusion**:
The metal that typically produces a white precipitate when H₂S is passed through its sulfate solution in the presence of NH₄OH is **Zinc (Zn)**, as zinc sulfide (ZnS) is known to form a white precipitate.

### Final Answer:
The metal is identified as **Zinc (Zn)**.