Which radicals are precipitated in `(NH_(4))_(2)CO_(3)` in presence of alkali

Options

A. `Ca,Ba,Sr`
B. `Mg`
C. Both
D. None of these

Explanation

To determine which radicals are precipitated in `(NH4)2CO3` (ammonium carbonate) in the presence of alkali, we can follow these steps:

### Step 1: Understand the Role of `(NH4)2CO3`
Ammonium carbonate acts as a source of carbonate ions (CO3^2-) when dissolved in water. In the presence of alkali, it can react with certain metal ions to form insoluble carbonates.

### Step 2: Identify the Radicals
We need to identify the basic radicals that can form precipitates with carbonate ions. Common metal ions that form insoluble carbonates include:
- Barium (Ba^2+)
- Strontium (Sr^2+)
- Calcium (Ca^2+)
- Magnesium (Mg^2+)

### Step 3: Analyze the Options
The options provided are:
1. Cadmium, Barium, or Strontium
2. Magnesium
3. Both or None of These

### Step 4: Determine Precipitation
- **Barium Carbonate (BaCO3)** and **Strontium Carbonate (SrCO3)** are both insoluble in water and will precipitate when barium or strontium ions are present with carbonate ions.
- **Magnesium Carbonate (MgCO3)** is also insoluble in water and will precipitate with magnesium ions.

### Step 5: Conclusion
Since both barium and strontium will precipitate in the presence of `(NH4)2CO3`, and magnesium will also precipitate, the correct answer is that both the first and second options are correct.

### Final Answer
The radicals that are precipitated in `(NH4)2CO3` in the presence of alkali are:
- Barium (Ba^2+)
- Strontium (Sr^2+)
- Magnesium (Mg^2+)

Thus, the correct choice is **"Both or None of These"**.

---