If 30 ml of `H_2` and 20 ml of `O_2` react to form water, what is left at the end of the reaction ?

Options

A. 10 ml of `H_(2)`
B. 5 ml of `H_(2)`
C. 10 ml of `O_(2)`
D. 5 ml of `O_(2)`

Answer

D

Explanation

`H_(2)+(1)/(2)O_(2)toH_(2)O`
1 mole `(1)/(2)` mole 1 mole
1 volume `(1)/(2)` volume
1 ml `H_(2)` reacts with `(1)/(2)`ml `O_(2)`
30 ml of `H_(2)` reacts with `=(1)/(2)xx30=15ml" "O_(2)`
(20-15)=50ml of `O_(2)` will left at the end of the reaction.