When 100 ml 1N-NaOH solution and 10 ml of 10 N sulphuric acid solution are mixed together, the resulting solution will be

Options

A. Alkali
B. Weakly acidic
C. Strongly acidic
D. Neutral

Explanation

To determine the nature of the resulting solution when 100 ml of 1N NaOH solution is mixed with 10 ml of 10N sulfuric acid solution, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the given values:**
- Volume of NaOH solution, \( V_1 = 100 \, \text{ml} \)
- Normality of NaOH solution, \( N_1 = 1 \, \text{N} \)
- Volume of sulfuric acid solution, \( V_2 = 10 \, \text{ml} \)
- Normality of sulfuric acid solution, \( N_2 = 10 \, \text{N} \)

2. **Calculate the equivalents of NaOH:**
- The number of equivalents of NaOH can be calculated using the formula:
\[ \text{Equivalents of NaOH} = N_1 \times V_1 = 1 \, \text{N} \times 100 \, \text{ml} = 100 \, \text{meq} \]

3. **Calculate the equivalents of sulfuric acid:**
- The number of equivalents of sulfuric acid can be calculated using the formula:
\[ \text{Equivalents of H}_2\text{SO}_4 = N_2 \times V_2 = 10 \, \text{N} \times 10 \, \text{ml} = 100 \, \text{meq} \]

4. **Compare the equivalents:**
- From the calculations, we have:
- Equivalents of NaOH = 100 meq
- Equivalents of H₂SO₄ = 100 meq
- Since the equivalents of NaOH and sulfuric acid are equal, they will completely neutralize each other.

5. **Determine the nature of the resulting solution:**
- When a strong base (NaOH) neutralizes a strong acid (H₂SO₄) in equivalent amounts, the resulting solution will be neutral.

### Conclusion:
The resulting solution after mixing 100 ml of 1N NaOH with 10 ml of 10N sulfuric acid will be **neutral**.