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Required amount of crystalline oxalic ac...

Required amount of crystalline oxalic acid (eq. wt. = 63 ) to prepare `(N)/(10)`, 250 ml oxalic acid solution is

A

0.158 g

B

1.575 g

C

15.75 g

D

6.3 g

Text Solution

Verified by Experts

The correct Answer is:
B
`N=(W_(B)xx1000)/(ExxV)implies(N)/(10)=(x xx1000)/(63xx250)" "thereforex=1.575gm`
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