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50 mL of 10 N H(2)SO(4), 25 mL of 12 N H...

`50 mL` of `10 N H_(2)SO_(4), 25 mL` of `12 N HCI` and `40 mL` of `5N HNO_(3)` are mixed and the volume of the mixture is made 1000 mL by adding water. The normality of resulting solution will be

A

1N

B

2N

C

3N

D

4N

Text Solution

Verified by Experts

The correct Answer is:
A
`H_(2)SO_(4)" HCl "HNO_(3)` Total volume
`N_(1)V_(1)+N_(2)V_(2)+N_(3)V_(3)=Nxx1000ml`
`N=(N_(1)V_(1)+N_(2)V_(2)+N_(3)V_(3))/(1000)`
`=(50xx10+25xx12+40xx5)/(1000)`
`N=(500+300+200)/(1000)=(1000)/(1000)=1N`
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