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0.1914 g of an organic acidi s dissolved...

0.1914 g of an organic acidi s dissolved in about 20 ml of water. 25 ml of 0.12 N NaOH is required for the complete neutralizatioonf the acid solution. The equivalent weight of the acid is

A

65

B

64

C

63.8

D

62.5

Text Solution

Verified by Experts

The correct Answer is:
C
Volume`=25ml=(25)/(1000)`litre
normality`=(wt)/(eq.wtxxvolume)implies0.12=(0.1914xx1000)/(Exx25)`
eq.wt.`=(0.1914xx1000)/(0.12xx25)=63.8`.
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