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0.126 g of acid required 20 mL of 0.1 N ...

0.126 g of acid required 20 mL of 0.1 N NaOH for complete neutralisation. The equivalent mass of an acid is

A

45

B

53

C

40

D

63

Text Solution

Verified by Experts

The correct Answer is:
D
20 ml of 0.1N NaoH neutralize 20 ml of 0.1 N acid weight of acid=0.126g
volume`=20ml=(20)/(1000)` litre
Normality`=0.1N,` equivalent weight=?
Equivalent weight`=("Weight of acid")/(NxxV)`
`=(0.126xx1000)/(0.1xx20)=63`
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