In 1 gram of ametal oxide, metal precipitated is 0.68 gm. What is the equivalent weight of metal

Options

A. 17
B. 34
C. 68
D. 52

Explanation

To find the equivalent weight of the metal, we can follow these steps:

### Step 1: Understand the relationship between metal oxide and metal
The metal oxide can be represented as \( MO \), where \( M \) is the metal and \( O \) is oxygen. When the metal oxide is reduced, the metal \( M \) is precipitated.

### Step 2: Calculate the weight of oxygen in the metal oxide
Given that the total weight of the metal oxide is 1 gram and the weight of the metal precipitated is 0.68 grams, we can find the weight of oxygen in the metal oxide.

\[ \text{Weight of oxygen} = \text{Weight of metal oxide} - \text{Weight of metal} \]
\[ \text{Weight of oxygen} = 1 \, \text{g} - 0.68 \, \text{g} = 0.32 \, \text{g} \]

### Step 3: Calculate the equivalent weight of oxygen
The equivalent weight of oxygen is known to be 8 grams (since the atomic weight of oxygen is 16, and its equivalent weight is half of that).

### Step 4: Calculate the equivalent weight of the metal
The equivalent weight of the metal can be calculated using the formula:

\[ \text{Equivalent weight of metal} = \frac{\text{Weight of metal}}{\text{Weight of oxygen} / \text{Equivalent weight of oxygen}} \]

Substituting the values we have:

\[ \text{Equivalent weight of metal} = \frac{0.68 \, \text{g}}{0.32 \, \text{g} / 8 \, \text{g}} = \frac{0.68 \, \text{g}}{0.04} = 17 \, \text{g} \]

### Conclusion
Thus, the equivalent weight of the metal is **17 grams**.

---