In the reaction `CH_3-Br+2Na+Br-CH_3 to `, the reaction is called

Options

A. Wurtz reaction
B. Aldol condensation
C. Perkin's reaction
D. Levit reaction

Answer

To determine the type of reaction represented by the equation \( \text{CH}_3\text{-Br} + 2\text{Na} + \text{Br-CH}_3 \), we need to analyze the components and the process involved.

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants in the equation are methyl bromide (\( \text{CH}_3\text{-Br} \)) and sodium metal (\( \text{Na} \)). We have two equivalents of methyl bromide reacting with two equivalents of sodium.

2. **Understanding the Reaction**:
This reaction involves two alkyl halides (methyl bromide) reacting with sodium. In organic chemistry, when two equivalents of an alkyl halide react with sodium, it often leads to the formation of a hydrocarbon.

3. **Recognizing the Type of Reaction**:
The reaction is characteristic of the Wurtz reaction. The Wurtz reaction is a coupling reaction where two alkyl halides react with sodium metal to form a higher alkane and sodium halide as a byproduct.

4. **Predicting the Product**:
In this case, the two methyl groups from the methyl bromide will couple together to form ethane (\( \text{C}_2\text{H}_6 \)). The byproducts will be sodium bromide (\( \text{NaBr} \)).

5. **Final Reaction Equation**:
The overall reaction can be summarized as:
\[ 2 \text{CH}_3\text{-Br} + 2 \text{Na} \rightarrow \text{C}_2\text{H}_6 + 2 \text{NaBr} \]

6. **Conclusion**:
Therefore, the reaction \( \text{CH}_3\text{-Br} + 2\text{Na} + \text{Br-CH}_3 \) is classified as a **Wurtz reaction**.