Electrolysis of cold concentrated aqueous solution of potassium succinate yields

Options

A. Ethane
B. Ethyne
C. Ethene
D. Ethane-1, 2-diol

Explanation

To solve the question regarding the electrolysis of cold concentrated aqueous solution of potassium succinate, we will follow these steps:

### Step 1: Identify the Components
Potassium succinate is the salt of succinic acid, which has the formula C4H6O4. In an aqueous solution, potassium succinate dissociates into potassium ions (K⁺) and succinate ions (C4H4O4²⁻).

### Step 2: Understand the Electrolysis Process
During electrolysis, the succinate ions (C4H4O4²⁻) will undergo oxidation at the anode. Oxidation involves the loss of electrons.

### Step 3: Oxidation of Succinate Ion
The succinate ion (C4H4O4²⁻) loses electrons and forms a radical. This radical can rearrange and undergo further reactions.

### Step 4: Decomposition of the Radical
The radical formed from the oxidation of the succinate ion can decompose to release carbon dioxide (CO2) gas. Specifically, two moles of CO2 can be released from the succinate radical.

### Step 5: Formation of Ethylene
After the loss of CO2, the remaining carbon radicals can dimerize (combine) to form ethylene (C2H4). This is the final product of the electrolysis process.

### Conclusion
Thus, the electrolysis of cold concentrated aqueous solution of potassium succinate yields ethylene (C2H4).

### Final Answer
The product of the electrolysis of cold concentrated aqueous solution of potassium succinate is ethylene (C2H4).

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