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The product of following reaction is CH3...

The product of following reaction is `CH_3-undersetunderset(CH_3)|oversetoverset(CH_3)|C-CH=CH_2underset((ii)NaBH_4)overset((i)Hg(OAc)_2, H_2O)to `

A

`CH_3-undersetunderset(CH_3)(|)oversetoverset(CH_2)|C-undersetunderset(OH)|CH-CH_2`

B

`CH_3-undersetunderset(CH_3)|overset(CH_3)overset|C-CH_2-CH_2OH`

C

`CH_3-undersetunderset(CH_3)|oversetoverset(OH)|C-oversetoverset(CH_3)|CH-CH_3`

D

`HOCH_2-undersetunderset(CH_3)|oversetoverset(CH_3)|C-CH_2-CH_3`

Text Solution

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The correct Answer is:
To solve the given reaction step by step, we will go through the two main reactions involved: oxymercuration and demercuration. ### Step 1: Understanding the Reactants The starting compound is: \[ CH_3 - C(CH_3)_2 - C = CH_2 \] This compound has a double bond between the last two carbon atoms. ### Step 2: Oxymercuration Reaction In the first step, we perform oxymercuration using mercury acetate (Hg(OAc)₂) and water (H₂O). According to Markovnikov's rule, the more substituted carbon will get the hydroxyl (OH) group, while the less substituted carbon will get the mercury acetate (Hg(OAc)). 1. **Breaking the double bond**: The double bond between the last two carbon atoms will break. 2. **Adding Hg(OAc) and OH**: The OH group will add to the more substituted carbon (the one with more hydrogens), and the Hg(OAc) will add to the less substituted carbon. The reaction will yield: \[ CH_3 - C(CH_3)_2 - C(OH) - C(HgOAc) \] ### Step 3: Demercuration Reaction In the second step, we perform demercuration using sodium borohydride (NaBH₄). This step replaces the mercury acetate (Hg(OAc)) with a hydrogen atom. 1. **Removing Hg(OAc)**: The Hg(OAc) group will be replaced by a hydrogen atom. 2. **Final Product Formation**: The final product will have an OH group on the more substituted carbon and a hydrogen on the less substituted carbon. The final product will be: \[ CH_3 - C(CH_3)_2 - C(OH) - CH_2 \] ### Final Product The final structure can be represented as: \[ CH_3 - C(CH_3)_2 - CH(OH) - CH_2 \] ### Conclusion Thus, the product of the reaction is: \[ CH_3 - C(CH_3)_2 - CH(OH) - CH_2 \]

To solve the given reaction step by step, we will go through the two main reactions involved: oxymercuration and demercuration. ### Step 1: Understanding the Reactants The starting compound is: \[ CH_3 - C(CH_3)_2 - C = CH_2 \] This compound has a double bond between the last two carbon atoms. ### Step 2: Oxymercuration Reaction ...
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Explore conceptually related problems

Addition of mercuric acetate in the presence of water is called as oxymercuration.The adduct obtained gives alcohol on reduction with NaBH_4 in alkaline medium.This is known as demercuration.Oxymercuration demercuration allows Markownikoff's addition of H, OH without rearrangement.The net result is the addition of H_2O Answer the following question : CH_3-undersetunderset(CH_3)(|)oversetoverset(CH_3)(|)(C)-CH=CH_2underset((ii)CH_3OH NaBH_4NaOH)overset((i)Hg(OAc)_2.THF)toAoverset(Hi(Conc.))toB Product B is :

Identify the product in the following reaction CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-CH=CH_(2)overset("Hg (OAc)"_(2l)H_(2)O)rarroverset(NaBH_(4))rarr 3, 3-Dimethyl - 1 - butene

Knowledge Check

  • CH_3-underset(CH_3)underset|overset(CH_3)overset|C-CH=CH_2 underset((ii)NaBH_4+NaOH)overset((i)Hg(CH_3COO)_2,THF)to ?

    A
    `CH_3-underset(CH_3)underset|overset(CH_3)overset|C-underset(OH)underset|CH-CH_3`
    B
    `CH_3-underset(CH_3)underset|overset(CH_3)overset|C-CH_2CH_2OH`
    C
    `CH_3-underset(CH_3)underset|overset(OH)overset|C-overset(CH_3)overset|CH-CH_3`
    D
    `HOCH_2-underset(CH_3)underset|overset(CH_3)overset|C-CH_2CH_3`
  • The product of the following reaction: CH_(3)- underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-CH=CH_(2) underset((ii)NaBH_(4))overset(((i)Hg(OAc)_(2),H_(2)O))to

    A
    `CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-underset(OH)underset(|)CH-CH_(3)`
    B
    `CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-CH_(2)-CH_(2)OH`
    C
    `CH_(3)-underset(CH_(3))underset(|)overset(OH)overset(|)C-underset(CH_(3))underset(|)CH-CH_(2)OH`
    D
    `HOCH_(2)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-CH_(2)CH_(3)`
  • The product of following reaction CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-CH=CH_(2)underset((ii). NaBH_(4)+NaOH)overset((i)Hg(CH_(3)COO)_(2),THF)to ?

    A
    `CH_(3)-underset(H_(3)C)underset(|)overset(CH_(3))overset(|)(C)-underset(OH)underset(|)(C)H-CH_(3)`
    B
    `CH_(3)-underset(H_(3)C)underset(|)overset(CH_(3))overset(|)(C)-C_(2)H-._(2)CHOI`
    C
    `CH_(3)-underset(H_(3)C)underset(|)overset(OH)overset(|)(C)-overset(CH_(3))overset(|)(C)H-CH_(3)`
    D
    `HOCH_(2)-underset(H_(3)C)underset(|)overset(CH_(3))overset(|)(C)-C_(2)H-CH_(3)`
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